2nd-Order System Example #2

Closed-Loop Poles with Added Pole

p = 1 p = 2 p = 5 p = 10 p = 20
-4.8549 -5.5926 -7.7513 -11.7551 -20.9054
-0.0725 + j1.8139 -0.2037 + j2.3833 -0.6244 + j3.1514 -1.1224 + j3.5144 -1.5473 + j3.5935
-0.0725 - j1.8139 -0.2037 - j2.3833 -0.6244 - j3.1514 -1.1224 - j3.5144 -1.5473 - j3.5935

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Lastest revision on Wednesday, June 7, 2006 12:08 PM